In which of the following compounds, nitrogen exhibits highest oxidation state?1. N3H2. NH2OH3. N3H. NH3
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nitrogen exhibits highest oxidation state in N3H
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N3H
3x + 1 = 0
x = -1/3
NH2OH
x + 3(+1) + (-2) = 0
x = -1
(Option 3 isn't clear but if it is supposed to be N2H4, then x = -2)
NH3
x + 3(+1) = 0
x = -3
So, option 1. N3H is the answer.
3x + 1 = 0
x = -1/3
NH2OH
x + 3(+1) + (-2) = 0
x = -1
(Option 3 isn't clear but if it is supposed to be N2H4, then x = -2)
NH3
x + 3(+1) = 0
x = -3
So, option 1. N3H is the answer.
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