Question

in which of the following has largest no of atoms? options a) 10 mole of calcium options b) 12000gram of carbon options c) 24 * 10^5 u of mg. options D) 800 gram of calcium

Answer 1

HEY MATE ✌✌✌✌✌✌✌✌✌✌


HERE IS YOUR ANSWER :-

a) 10 mole of calcium ,

we know that ,

no of mole = no of atoms / 6.023 * 10^23

10 = no of atoms / 6.023 * 10^23

no of atoms = 10 * 6.023 * 10 ^23

B) 12000 gram of carbon ,

we know that ,

no of mole = mass in gram / atomic mass in gram

= 12000/12

=1000

after that ,

no of mole = no of atoms / 6.023 * 10^23

1000 = no of atoms / 6.023 * 10^23

no of atoms = 1000 * 6.023 * 10^23

c) 24 * 10^5 u of mg

we know that ,

no of atoms = given u / atomic mass u

= 24 * 10 ^5 u / 24

= 10^5

d) 800 gram of calcium

we know that ,

no of mole = mass in gram / atomic mass in gram

= 800/ 40

= 20

after that ,

no of atoms = 20 * 6.023 * 10^23


hence ,

options B has largest no of atoms

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