Chemistry, asked by SerenaSmith1227, 1 year ago

Ph3(phosphine) when passed in aqueous solution of cuso4 produces

Answers

Answered by Anonymous
38
HEY FOLK...

Below is the balanced chemical reaction for ur question:-

3CuSO₄ + 2PH₃ -----> Cu₃P₂ + 3H₂SO₄

Thank you

HOPE IT HELPS..!
Answered by RomeliaThurston
11

Answer: It produces Copper (II) phosphide, sulfuric acid and water.

Explanation:

When phosphine is passed onto the aqueous solution of copper sulfate, it produces multiple of products.

The equation for the reaction between the two follows:

3CuSO_4.5H_2O(aq.)+2PH_3\rightarrow Cu_3P_2+3H_2SO_4+15H_2O

By Stoichiometry of the reaction:

3 moles of copper sulfate reacts with 2 moles of phosphine to produce 1 mole of copper (II) phosphide, 3 moles of sulfuric acid and 15 moles of water.

Hence, it produces Copper (II) phosphide, sulfuric acid and water.

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