In XeF2,XeF4,XeF6 number of lone pairs on Xe are???
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In XeF₂,total number of valence electrons of Xe=8, two electrons are shared with 2F atoms,6 electrons are left hence 3 lone pairs.
In XeF₄,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs.
In XeF₆,total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair.
In XeF₂,total number of valence electrons of Xe=8, two electrons are shared with 2F atoms,6 electrons are left hence 3 lone pairs.
In XeF₄,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs.
In XeF₆,total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair.
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Question:
In XeF2,XeF4 and XeF6, the number of lone pairs of Xe is???
Solution:
Xe has total of 8 valence electrons.
In XeF2, 2 electrons are shared thereby leaving three lone pair of electrons.
In XeF4, 4 electrons are shared thereby leaving two lone pair of electrons.
In XeF6, 6 electrons are shared thereby leaving one lone pair of electrons.
Hence, No of lone pair of electrons in XeF2, XeF4, XeF6 are 3,2,1 respectively.
Note: Figures showing lone pairs are attached to get a better idea.
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