INA TWO DIGIT NUMBER THE SUM OF TWO DIGITS IS8IF 8 IS ADDED TO THE NUMBER IT'S DIGITS ARE REVERSED.FIND THE NO.S frnds plzzzzzzzzzzzzzzzzzzz answer fast
Answers
Answered by
3
let the two digit numbers be 10x+y
given x+y = 8 ----------- (1)
x = 8-y
10x+y+8 = 10y+x
10x+y+8-10y-x = 0
9x-9y+8 = 0
9(8-y)-9y+8 = 0
72- 9y - 9y +8 = 0
90- 18y = 0
18y = 90
y = 90/18
y = 5
sub y = 5 in (1)
x+5 = 8
x = 3
the number 10x+y = 10(3)+5
= 30+5
= 35
the two digit number is 35
the two digit number after reversing is 43.
given x+y = 8 ----------- (1)
x = 8-y
10x+y+8 = 10y+x
10x+y+8-10y-x = 0
9x-9y+8 = 0
9(8-y)-9y+8 = 0
72- 9y - 9y +8 = 0
90- 18y = 0
18y = 90
y = 90/18
y = 5
sub y = 5 in (1)
x+5 = 8
x = 3
the number 10x+y = 10(3)+5
= 30+5
= 35
the two digit number is 35
the two digit number after reversing is 43.
bhaghi:
thanks for marking as best
Answered by
3
I think bhaghi made a minor error at the end, 35 is your two digit, Reversed, is 53. Bhaghi explains how to solve it above (or below)
Similar questions