Question

Initial velocity of an object in the direction of OE is 3m/s. A force of 5N is applied on the body

perpendicular to the direction of OE .Find the distance of the object towards OE after 4s.

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Answer 1

Velocity, VOE=3 m/s

Since, applied force is perpendicular to OE so the velocity VOE will be constant.

So, displacement along OE in 4 sec SOE=3×4=12 m

Along OF

Force applied, F=4 N

Mass of the body, m=2 kg

So, acceleration a=mF=2 m/s2

Displacement along OF in time t=4 sec

SOF=ut+21at2

SOF=0+21×2×42

SOF=16 m

After t=4 sec, the distance of the body from O to OP

OP2=122+162

OP2=144+256

OP2=400

OP=20 m



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