inner and Outer radii of a metallic pipe are 3 cm and 3.5 CM respectively. If length of the pipe is 56cm,find total surface area
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The total surface area of the pipe is 2308.6 cm².
Given data :
Inner and Outer radii of the pipe are = 3 cm and 3.5 cm
Length of the pipe = 56 cm
So,
Inner surface area = 2 × π × 3 × 56 = 1056 cm²
Outer surface area = 2 × π × 3.5 × 56 = 1232 cm²
Top and bottom circular ring area = [2× {(π×3.5×3.5)-(π×3×3)}]
= {2×(38.5-28.2)}
= 2× 10.3
= 20.6 cm²
Total surface area = ( inner surface area + outer surface area + top and bottom circular ring area ) = (1056+1232 + 20.6 ) = 2308.6 cm² (answer)
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