Question

insert 3 gp between 1/9 and 9​

Answer 1

Step-by-step explanation:

1/9, G1, G2, G3, 9

we know that r = (b/a)^1/(n+1)

= 3 where a=1/9

b=9

G1= ar= 1/9 ×3= 1/3

G2= ar^2=1/9×9=1

G3= ar^3= 1/9×27=3

it is called GM . it is not gp.