Math, asked by Smeenu2869, 1 year ago

Insert arithmetic mean between 7 and 71 in such a way that the 5th arithmetic mean is 27 find number of arithmetic means

Answers

Answered by MRABHI18664
13

7, __, __, __, __, 27, ..., 71

27 is the 5th term BEYOND 7, so it's the 6th term

INCLUDING 7. So we begin with n=6

a1 = 7

a6 = 27

an = a1 + (n-1)d

Substitute n=6

a6 = a1 + (6-1)d

27 = 7 + 5d

20 = 5d

4 = d

Now we substitute an = 71

an = a1 + (n-1)4

71 = 7 + (n-1)4

71 = 7 + 4(n-1)

71 = 7 + 4n - 4

71 = 3 + 4n

68 = 4n

17 = n

So there are 17 terms, and the entire sequence is

7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59, 63, 67, 71

Edwin

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Answered by niranjananil
1

Answer:

Step-by-step explanation:heres the imagee broh

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