Insert arithmetic mean between 7 and 71 in such a way that the 5th arithmetic mean is 27 find number of arithmetic means
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7, __, __, __, __, 27, ..., 71
27 is the 5th term BEYOND 7, so it's the 6th term
INCLUDING 7. So we begin with n=6
a1 = 7
a6 = 27
an = a1 + (n-1)d
Substitute n=6
a6 = a1 + (6-1)d
27 = 7 + 5d
20 = 5d
4 = d
Now we substitute an = 71
an = a1 + (n-1)4
71 = 7 + (n-1)4
71 = 7 + 4(n-1)
71 = 7 + 4n - 4
71 = 3 + 4n
68 = 4n
17 = n
So there are 17 terms, and the entire sequence is
7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59, 63, 67, 71
Edwin
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Answer:
Step-by-step explanation:heres the imagee broh
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