Question

int sin power 4 x dx ​

Answer 1

-cos⁴x.dx

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Answer 2

Answer:

(Sin square x.) Ki power square dx

(1-cos2x\2)ki power square dx

1\4(1-cos2x) ki power square dx

1\4+1+cos square 2x-2cos2x) dx

1\4x+1\4 {(1+cos2x\2)-2(sin2x\2)dx

1\4 [x+1\2+1\2sin4x\4-1\2sib2x] dx

1\4[2x+x\2+sub4x\8-sib2x] +c

3x\8+sib4x\32-sin2x\4]+c

3x\8-1\4sin2x+1\32sib4x+c