Question

integral 3cosx-2sin2x/cos2xsin3xdx
do it correctly​

Answer 1

Step-by-step explanation:

6 power -3

(6)-3 power

1/6 power 3 ( by replacing the negative sign into positive sign)

1 multiply by 3

6 multiply by 6 power 3

1/216 is the answer ...

so 6 power -31 is equal to 1/216 ....

Answer 2

Step-by-step explanation:

3sinx−2cosx+C

Explanation:

∫(2sinx+3cosx)dx=2⋅∫sinxdx+3⋅ ∫cosxdx

Applying standard integrals:

=2⋅(−cosx)+3⋅sinx+C

=3sinx−2cosx+C

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