Integral of cot theta/2
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Given : cot(θ/2)
To Find : Integral
Solution:
cot(θ/2)
= cos(θ/2)/sin(θ/2)
Let say sin(θ/2) = x
=> cos(θ/2) (1/2) dθ = dx
=> cos(θ/2)dθ = 2dx
∫ cot(θ/2) dθ
= ∫ 2dx/x
= 2 ∫ (1/x)dx
= 2 ln | x | + C
= 2 ln | sin(θ/2) | + C
∫ cot(θ/2) dθ = 2 ln | sin(θ/2) | + C
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