Question

integral root 1-x²/1+x²​

Answer 1

Step-by-step explanation:

1-x^2/1+x^2

now,

1/1+x^2-x^2/1+x^2

=1/1+x^2-x^2+1-1/1+x^2

=tan-1x-x-tan-1x +c

tan inverse