Question

integrate 3t²+2t+t+10 dt when t varies from 0 to 2​

Answer 1

Answer:

9

Step-by-step explanation:

3t^2+2t+t+10

3t^2+ 3t+ 10

on integrating we get

[3t]/1 + 3 + 0

now t varies from 0 to 2

so we get,

[3(2) - 3(0)] + 3

3(2) + 3

6+3

9

Answer 2

Answer:

34

Step-by-step explanation: