integrate (sinx) whole cube.With respect to x.
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theAmankr:
sorry but there is calculation error
where
sorry,i was commenting on other question
k no problem mine is correct right
yes, I was looking for other process
ok
i think this is the only process which is simple
thanks bro thanks a lot it means a lot to me
for what
marking as brainleist
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We know that
sin3x =3sinx −4(sinx)3 = 4(sinx)^3 = 3sinx − sin3x = (sinx)^3 = (3/4 *sinx) −₹1/4*sin3x)
Hence we have that
∫(sinx)^3 dx = ∫(3/4⋅sinx − 1/4⋅sin(3x))dx=−3/4cosx + 1/12cos3x + c
sin3x =3sinx −4(sinx)3 = 4(sinx)^3 = 3sinx − sin3x = (sinx)^3 = (3/4 *sinx) −₹1/4*sin3x)
Hence we have that
∫(sinx)^3 dx = ∫(3/4⋅sinx − 1/4⋅sin(3x))dx=−3/4cosx + 1/12cos3x + c
thanks for your efforts
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