integrate the given functions with respect to x:
answer fast with step wise explanation please.
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Answered by
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1) int. cos(2x) dx
= int. 2 sin x cos x dx
Since, sin 2x = 2 sin x cos x
So,
int. 2 sin x cos x = - 2x sin x cos x + c
where c is the integral constant.
= int. 2 sin x cos x dx
Since, sin 2x = 2 sin x cos x
So,
int. 2 sin x cos x = - 2x sin x cos x + c
where c is the integral constant.
AdiK1needy:
1. cos2x ≠ 2 sinx cosx
ohh I'm very sorry
i just got confused
your calculations is wrong
wait a minute I'll just edit the answer
anyway thanks for looking my answer
oh man you reported the answer
how do i answer you now?
alright man
when this answer gets deleted you can try answering another time I do it to give experts a chance other than the spammers
Answered by
1
Answer:
1) int. cos(2x) dx
= int. 2 sin x cos x dx
Since, sin 2x = 2 sin x cos x
So,
int. 2 sin x cos x = - 2x sin x cos x + c
where c is the integral constant.
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