integration of
integration of
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Answered by
1
let suppose sinx = t²
cosx dx = 2tdt
dx = 2tdt/cosx
dx = 2tdt/√1-t²
now use integration rule and you get integrated form
cosx dx = 2tdt
dx = 2tdt/cosx
dx = 2tdt/√1-t²
now use integration rule and you get integrated form
Answered by
0
2/3 (cube root of square of sinx /cosx )
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