Question

integration of (x^2 +1)logx dx​

Answer 1

Answer:

this is the answer

Answer 2

Answer:

logx(x^3/3+1x)- (1/x( x^3/3+x)

Explanation:

{ x^2+1} logx dx

x^2+1/2+1+1 x^0+1/0+1)logx- d/dx(logx)

(x^3/3+1x )logx- (1/x[x^3/3+1x) this is the answer

formula used in this question

log x integration is 1/x

x^n= x^n+1/n+1

hope it helps

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