interior angles obtained on producing the wall of triangles both way are 104 and 136 find angles of triangle
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From the adjacent figure,
the exterior angle ∠ACD=136°
∴, ∠ACB=180°-136°=44°
the other exterior angle, ∠ABE=104°
∴, ∠ABC=180°-104°=76°
∴, ∠BAC=180°-(∠ABC+∠ACB)
=180°-(76°+44°)
=180°-120°
=60°
∴, the angles of the given triangle are: 76°,60° and 44° Ans.
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