Internal energy of a gas obeying van der waals equation depends on
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Since the options are not given, I am giving a general answer.
The internal energy of a gas which obeys the Vanderwaal's equation - depends on the specific volume and the temperature.
For a Vanderwaal's gas, the internal energy can be computed from the equation-
The internal energy of a gas which obeys the Vanderwaal's equation - depends on the specific volume and the temperature.
For a Vanderwaal's gas, the internal energy can be computed from the equation-
(δE / δV) T = T (δP /δT) V – P
But, P = RT / (v-b) – a/v²
(δP / δT) V = R / v - b
(δE / δV) T = T (R / v - b) – [(RT / v - b) – (a / v²) = a / v²
(δE / δV) T = αT Kt - P
Kt = -v (δP / δV) T = -v (2a / v³) = -2a / v²
So, (δcV / δV) T = T (δ²P / δT²) = 0
d ∈ = cV (T) dT + (a / v2) dv.
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