Question

intriangle ABC right angle at B AB=24 BC=7 what is sinA × cosC

Answer 1

here, 
     AB=24 and BC=7
then, CA=25 
  also,  sinA * cosC=sinA*cos[90-A]{as cosC=cos[90-A]
                               =sinA*sinA  {as cos[90-A]=sinA}
                                =$[sinA]^2$
and sinA=BC/CA
               =7/25
THEREFORE,
 sinA*cosC=$[sinA]^2$
                  =[7/25]^2
                  =49/625              [ans]

Answer 2

Heya user !!

Here's the answer you are looking for

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