ir | sec* (7 - 4x)dx = a tan (2 - 4x) + C. then value of a is
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Answer:
MATHS
Solve ∫sec
2
(7−4x)dx
MEDIUM
ANSWER
∫sec
2
(7−4x)dx
=tan(7−4x)
dx
d
(7−4x)+c
=tan(7−4x)(−4)+c
=−4tan(7−4x)+c (Ans)
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