Question

IS 101 a term of the series 5,7,9....​

Answer 1

Yes , 101 is a term of the given series 5,7,9,.....to nth term

$\mathbb{REASON}\rightarrow$

as the common ratio / difference of the term is 2

if the $S_n$ value is given , you can also show the equation

Answer 2

Answer:

Yes, it is the 50th term

Step-by-step explanation:

Let 101 be the $N_{th}$ term of the A.P

Here, a = 3, $a_{2}$ = 5

d = $a_{2}$ – a

d = 5 - 3 =  2

$a_{n}$ = a + (n-1)d

101 = 3 + (n-1) 2

101 - 3 = (n - 1 ) 2

98 =  (n - 1 ) 2

$\frac{98}{2}$ = n - 1

49 = n - 1

n = 49 + 1

  = 50