Question

is Factorable? why?
$6x { }^{2} - 2x + 1$
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Answer 1

Answer:

6x² - 2x + 1

Let's use the AC Method.

First multiply the coefficient ( A=6 ) of the x² term by the coefficient ( C=2) of the constant term - ignoring the sign.

AC=6⋅2=12

Notice that the sign of the constant ( C ) term is negative.

According to the AC Method, we need to look for

a factorisation of our AC

value into a pair of factors, whose difference is the middle coefficient B=1

Well 4×3=12 and 4−3=1

So the pair we want is 4 and 3

Now use this pair to split the middle term then factor by grouping:

6x²−x−2=6x²−4x+3x−2

=(6x²−4x)+(3x−2)

=2x(3x−2)+(3x−2)

=(2x−1)(3x−2)

Step-by-step explanation:

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