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given √3 = 2.732
to evaluate (√3+1)/(√3-1)
first step is to eliminate the radical sign (√) in the denominator by multiplying both Nr and Dr by
the conjugate of Dr ie (√3+1)
= [(√3+1)(√3+1)]/ [ (√3-1)(√3+1)]
= (√3+1)^2/(3-1) [ (a-b)(a+b) = a^2-b^2 ]
= (3 + 1 + 2√3)/2
= (4+2√3)/2
= 2(2+√3)/2
= 2+√3 [ 2 cancels out in Nr and Dr ]
now putting the value of √3 in the above simplified expression,
2+√3 = 2+1.732 = 3.732 Answer
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