Question

is it Divisibility by 9 : do with a rule add but divide show me steps a)678908 b)12141 c)98768 d)2563713

Answer 1

Answer:

b and d is correct

Step-by-step explanation:

$a) \: 6 + 7 + 8 + 9 + 0 + 8 = 38 \\ 3 + 8 = 11 \: and11is \: not \: divisible \: by \: \\ 9 \\ therefore \: 68908 \: is \: not \: divisible \: by \: \\ 9 \\ b)1 + 2 + 1 + 4 + 1 = 9 \\ 9is \: divisible \: by \: 9 \: so \:12141 \ \: \: is \: \\ divisible \:by \: 9 \\ d)2 + 5 + 6 + 3 + 7 + 1 + 3 = 27 \\ 2 + 7 = 9 \\ 9is \: \\ divisible \: by \: 9 \: so \: 2563713is \: \\ divisible \: by \: 9 \\ c)9 + 8 + 7 + 6 + 8 = 38 \\ 3 + 8 = 11 \\ 11is \: not \: divisible \: by \: 9 \: so \: 98768 \: is \: \\ not \: divisible \: by \: 9$

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Answer 2

Answer:

LETS FIND OUT

a) 678908

= 6+7+8+9+0+8

= 38

∴ 38 is not in the table of 9. So, 678908 is not divisible by 9.

b) 12141

=1+2+1+4+1

=9

∴ 9 is in the table of 9. 9 x 1=9. So, 12141 is divisible by 9.

c) 98768

= 9+8+7+6+8

= 38

∴ 38 is not in the table of 9. So, 678908 is not divisible by 9.

d) 2563713

= 2+5+6+3+7+1+3

= 27

∴ 27 is in the table of 9. 9x3=27. So, 2563713 is divisible by 9