Math, asked by apoorvakumari, 1 year ago

is it right? I don't know how to remove this 2

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Answered by clockkeeper
1

oh! You made a blunder in the 3rd step of L.H.S and in the 2nd step of R.H.S

Actually

after \\  \sin( \alpha )  \div ((1 +  \cos( \alpha ) ) \div  \sin( \alpha ) ) \\ it \: is \\  { \sin( \alpha ) }^{2}  \div (1 +  \cos( \alpha ) ) \:  \: in \: l.h.s.

and, in R.H.S.

after \\ 2 +  \sin( \alpha )  \div (( \cos( \alpha )  - 1) \div  \sin( \alpha ))  \\ it \: is \\ 2 +  ({ \sin( \alpha ) }^{2}  \div ( \cos( \alpha )  - 1))

and the rest you can do all by yourself


apoorvakumari: yah i got it...i was confused...thanks a lot
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