Physics, asked by dangsacrsmaring, 3 months ago

Is Lenz's law is used to determined direction of alternating current?

Answers

Answered by ThunderGirl

0

Answer:

Therefore, Lenz's law can be used to determine the direction of emf induced in the coil but not its magnitude.

Explanation:

hope it helps you

Answered by Kshitu73

2

Therefore, Lenz's law can be used to determine the direction of emf induced in the coil but not its magnitude.

Hope it helps.... ✌️

Previous Question

Next Question

Similar questions

Math, 1 month ago

If G is a finite group and H is a normal subgroup of G, then o(G\H) is...

Math, 1 month ago

Niveditha ranked 8th from the top and 27th from the bottom in a class. How many students are there in the class??

Social Sciences, 1 month ago

Panuto: Basahin at unawain ang talata. Sagutin ang mga sumusunod na katanungan. Panganay si Andres Bonifacio sa anim na magkakapatid. Labing- apat na taon si Andres nang mamatay ang kaniyang magulang. Gumawa at nagtinda siya ng abanikong papel at tungkod na kahoy. Pumasok siyang mensahero sa isang kompanya. Naging ahente rin siya ng iba pang kompanya. 8-9. Ano ang paksa ng napakinggang talata?

Chemistry, 3 months ago

पृथ्वी को गर्म रखती है।...

India Languages, 3 months ago

minnangal kaditham tamil letter writing kalavu ponna poralai meattu tharum aga alluvalarukaga...

Chemistry, 8 months ago

Consider the reaction CH₃ - CH - CH₃ + Br₂ □(→┴Light, 400K ) | CH₃ CH₃ | CH₃ - CH - CH₂Br + CH₃ - C - CH₃ | | CH₃ Br (I) (II) (a) Compounds I and II are formed in nearly equal amounts (b) Compounds I is formed in larger proportions (c) Compounds II is formed in larger proportions (d) Relative amount of II cannot be predicted...

Chemistry, 8 months ago

The hydrocarbon which can react with sodium in liquid ammonia is (a) CH₃CH₂CH₂C ≡ CCH₂CH₂CH₃ (b) CH₃CH₂C ≡ CH (c) CH₃CH = CHCH₃ (d) CH₃CH₂C ≡ CCH₂CH₃...

Chemistry, 8 months ago

In the following reaction, C₆H₅CH₂Br □(→┴1.Mg,Ether ) X, the product ‘X’ is (a) C₆H₅CH₂CH₂C₆H₅ (b) C₆H₅CH₂OCH₂C₆H₅ (c) C₆H₅CH₂OH (d) C₆H₅CH₃...