Question

∆ is right angled at P. PS is perpendicular to QR. If PQ = 5 cm, QR = 13 cm and PR = 12 cm, Find the area of ∆ . Also find the length of PS.

Answer 1

Step-by-step explanation:

Answer

=>

In ΔPQR

(PR)

2

=(PQ)

2

+(QR)

2

(PR)

2

=(12)

2

+(5)

2

(PR)

2

=169

PR=13

Now AOBQ is a square

So, QB=x

Then, BR=5−x

Similarly AQ=x

Then AP=12−x

Also, CR=BR

CR=5−x

[∵ Length of tangents drawn from external point are equal]

And, CP=AP=12−x

[∵ Length of tangents drawn from external point are equal]

PR=PC+CR

13=5−x+12−x

2x=4⇒x=2 cm.

This is your answer...