Question

Is saying
11sec = 10(y-3) / (y-5) km/h okay

Answer 1

Answer:

Yes

x10+y5−1=0 ...(i)  

and  x8+y6=15 ...(ii)

Now, multiplying both sides of Eq. (i) by LCM (10,5)=10, we get

x+2y−10=0

⇒ x+2y=10 ...(iii)

Again, multiplying both sides of Eq. (iv) by LCM (8,6)=24, we get

3x+4y=360 ...(iv)

On, multiplying Eq. (iii) by 2 and then subtracting from Eq. (iv), we get

3x+4y=3602−x+4−y=2−0−−−−−−−−−−− x=340

Put the value of x in Eq. (iii), we get

340+2y=10

⇒ 2y=10−340=−330

⇒ y=−165

Given that, the linear relation between x, y and λ is

y=λx+5

Now, put the values of x and y in above relation, we get

−165=λ(340)+5

⇒ 340λ=−170

⇒ λ=−12