is the above question correct or not.
give reason too.
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no.. this kind of transformation is used when u want to express the rate of change of velocity with respect to displacement instead of time.. the correct transformation is attached.. hope this helps
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which means the v cannot be directly multiplied to dv/ds
ight got it loads of thanks
no.. dv/ds actually means derivative of v with respect to s.. so it cannot be multiplied directly..
hmm yes , moreover, differentiating dv sq with respect to ds wont give me v.( dv/ ds) .
thanks a lot saviour
welcome..
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