is the sequence in a GP
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yes it is a sequence in G.P.
here a=1/3,r=1/3
n=9
we know that
a↓n=ar↑n-1
a↓9=1/3(1/3)↑8
=1/3(1/6561)
=1/19683
here a=1/3,r=1/3
n=9
we know that
a↓n=ar↑n-1
a↓9=1/3(1/3)↑8
=1/3(1/6561)
=1/19683
ghdghj:
can u tell the answer what is it 9 th term
here a=1/3, r=1/3
9 th term
not a or r
check the answer
i dont have solution book with me
i have modify my answer
ok
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