Is the velocity v of a particle varies as the square of its displacement x then the acceleration varies as?
Answers
Answered by
1
Answer: a = 2x
Explanation: As v= x^2
Or, dv/dt = 2x
And we know that dv / dt = a
So , a = 2x
Here, v = velocity
x = displacement
a = acceleration
Answered by
0
Answer:
a=x^2
Explanation:
THE CORRECT ANSWER IS 2X^2
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