Physics, asked by madhurjyalaskar9791, 11 months ago

Is the velocity v of a particle varies as the square of its displacement x then the acceleration varies as?

Answers

Answered by MEGHASandhi
1

Answer: a = 2x

Explanation: As v= x^2

Or, dv/dt = 2x

And we know that dv / dt = a

So , a = 2x

Here, v = velocity

x = displacement

a = acceleration

Answered by yashreddy2021
0

Answer:

a=x^2

Explanation:

THE CORRECT ANSWER IS 2X^2

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