Is this figure RHS or ASA?? Pls tell!
Answers
I think it is nor R.H.S nor ASA. According to me it should be SAS.
Step-by-step explanation:
It is not R.H.S because RHS congruence theorem states that, if the hypotenuse and side of one right-angled triangle are equal to the hypotenuse and the corresponding side of another right-angled triangle, the two triangles are congruent. but your figure has not mentioned the hypotenuse to be equal.
It is not ASA because, because ASA congruency states that If any two angles and side included between the angles of one triangle are equivalent to the corresponding two angles and side included between the angles of the second triangle, then the two triangles are said to be congruent by ASA rule. So, you can clearly understand by seeing the figure that two angles and one side is not included. so it is not ASA.
I think that it must be SAS because, here in this figure two sides and one angle is included.
hope it helped you.....
Answer:
The given triangles are congruent by SAS congruency.
Explanation:
★ The RHS congruency rule states that a right angled triangle is said to be congruent with another right angled triangle if one side and hypotenuse of one triangle is congruent to the hypotenuse and one side of the other triangle.
90° + Hypotenuse + One Side = 90° + Hypotenuse + One Side ----- RHS
Here we can see that the hypotenuses are not congruent.
Hence the two triangles are not congruent by RHS rule of congruency.
★ The SAS congruency rule states that if two sides and included angle of one triangle is equal to the two sides and included angle of another triangle, then they are congruent by SAS rule.
In ΔABE and ΔBCD,
AB = CD [Given]
∠A = ∠C [90°]
AE = BC [Given]
Hence ΔABE ≅ ΔBCD by SAS congruency rule.
Therefore, we can confirm that the given triangles are congruent by SAS rule and not RHS.