IS
what is the coefficient of friction if a force of 30N
required to move a body of mass 35 kg (irg - 10NJ?
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It is given that
Sum of two rational numbers =12−7
One of the rational number =2413
Other rational number =x
2413+x=12−7
x=12−7−2413
LCM of 12 and 24 is 24
=12×2−7×2−2413
By further calculation
=24−14−2413
So we get
=24−14−13
=24−27
=8−9
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