Is zero a term of the AP -99,-95,-91,...
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Here,
d=-95-(-99)=+4
Now,let Tn=0{nth term be 0}
then,
a+(n-1)d=0
=>-95+(n-1)4=0
on solving we would get n=fraction.
Hence,0 can't be a term of this A.P.
Hope it helps!
d=-95-(-99)=+4
Now,let Tn=0{nth term be 0}
then,
a+(n-1)d=0
=>-95+(n-1)4=0
on solving we would get n=fraction.
Hence,0 can't be a term of this A.P.
Hope it helps!
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