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1.) Fence= perimeter of field=150
let breadth be x
length=2x
2(2x+x)=150
3x=75
x=25
2.) Let the number be A,
2A-8=58,
then
2A=58+8,
2A=66,
then
A=33
l=50m
b=25 m
3.) As per question 5x+7=37
x=37-7/5
=30/5
=6 ans
4.) Since it is an isosceles triangle
Base angles would be equal.
So,let the required angle be x
By Angle Sum Property of Triangle
angle A+x+x=180°
50+2x=180°
2x=130°
x=130/2°
x=65°
Therefore required angles are 65° each.
let breadth be x
length=2x
2(2x+x)=150
3x=75
x=25
2.) Let the number be A,
2A-8=58,
then
2A=58+8,
2A=66,
then
A=33
l=50m
b=25 m
3.) As per question 5x+7=37
x=37-7/5
=30/5
=6 ans
4.) Since it is an isosceles triangle
Base angles would be equal.
So,let the required angle be x
By Angle Sum Property of Triangle
angle A+x+x=180°
50+2x=180°
2x=130°
x=130/2°
x=65°
Therefore required angles are 65° each.
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