It is found that ce4+ is a good oxidizing agent whereas sm2+ is a good reducing agent. state the reason for this difference
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The most stable oxidation state in Lanthanoids is +3. Thus ce4+ undergoes reduction where its oxidizing agent gets reduced as the reduction involves a decrease in oxidation state and gain of electrons.
Hence, ce4+ is known as a good oxidizing agent. Sm2+ undergoes oxidation which involves an increase in the oxidation state and loss of electrons. Hence, sm2+ also behaves as a good reducing agent.
Hence, ce4+ is known as a good oxidizing agent. Sm2+ undergoes oxidation which involves an increase in the oxidation state and loss of electrons. Hence, sm2+ also behaves as a good reducing agent.
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