it is given O is center then find x
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angle OAC = angleOCA. =50 (OA=OC(radius of cirle )
similarly angleOCB =angleOBC=20
angleACB= angle ACO+ angle BCO
angleACB = 50+20=70
so
angleAOB(x) = 2angleACB. ( angle subtended by an arc at centre is double the angle subtended by it on circle)
therefore
x=2×70=140
similarly angleOCB =angleOBC=20
angleACB= angle ACO+ angle BCO
angleACB = 50+20=70
so
angleAOB(x) = 2angleACB. ( angle subtended by an arc at centre is double the angle subtended by it on circle)
therefore
x=2×70=140
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