It is given that 3a+2b=5c,then find the value of 27a³ + 8b³- 125c³ if abc
=0
Answers
Answered by
19
3a+2b=5c
(3a+2b-5c)^3=0^3
27a^3+8b^3-125c^3-3×3a×2b×5c=0
27a^3+8b^3-125c^3-90abc=0
so,
27a^3+8b^3-125c^3=0
(3a+2b-5c)^3=0^3
27a^3+8b^3-125c^3-3×3a×2b×5c=0
27a^3+8b^3-125c^3-90abc=0
so,
27a^3+8b^3-125c^3=0
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Answered by
6
3a+8b=5c then 3a+8b-5c=0
27a^3+8b^3-125c^3=>
(3a)^3+(2b)^3=(-5c)^3 = 3(3a)*(2b)*(-5c)= -90abc
-90*0
0
27a^3+8b^3-125c^3=>
(3a)^3+(2b)^3=(-5c)^3 = 3(3a)*(2b)*(-5c)= -90abc
-90*0
0
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