it is required to reduce the volume of a gas by 20% by compressing it at a constant pressure to do so the gas has to be cooled if the gas attends A final temperature of 157 degree Celsius find the initial temperature of the gas
Answers
P1V1/T1 = P2V2/T2 , but omit P because it is constant.
For volume you can use a ratio: 100 to 80 or 1 to 0.8 whichever you find convenient. I will use 1 to 0.8 Now substitute into the equation , temperature in K : 157°C = 430K
V1/T1 = V2/T2
1/T1 = 0.8/430
T1 = 430/0.8
T1 = 537.5 K
Original temperature = 537.5- 273 = 265°C
Explanation:
let the initial volume is V1=100V
If the volume is reduced by 20% therefore it becomes... V2=100V--20V =80V
here given
initial temperature is T1=T
final temperature is =T2=157+273=430K
therefore according to Charles law.,
\frac{v1}{t1} = \frac{v2}{t2}
t1
v1
=
t2
v2
NOW
\frac{100}{t1} = \frac{80}{430}
t1
100
=
430
therfore
t1=
80
100×430
=
80
43000
t1 = \frac{4300}{8} = 537.5 \: kelvint1=
8
4300
=537.5kelvin
hence the final temperature is 537.5 K. or 300K