It is required to sterilize 100l of medium which contains 30000 microorganisms/ml. if expected contamination probability is 10^-3. the secific death rate for given sterilization is 0.23 minutes. find time required to achieve this
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Given the probability of contamination, we can get the amount of contaminated water :
Probability = 0.001
From the total capacity of 100 L which is equivalent to 100000ml we can get the capacity contaminated :
0.001 × 100000 = 100ml
Contamination rate is :
30000 microorganisms per ml
Thus the total microorganisms is :
30000 × 100 = 3000000 microorganisms.
The death rate is :
0.23 minutes for 1ml that is it takes 0.23 minutes to kill 30000 microorganisms.
The total time taken is thus :
3000000 / 30000 × 0.23 = 23 minute.
The time taken is thus :
23 minutes.
Probability = 0.001
From the total capacity of 100 L which is equivalent to 100000ml we can get the capacity contaminated :
0.001 × 100000 = 100ml
Contamination rate is :
30000 microorganisms per ml
Thus the total microorganisms is :
30000 × 100 = 3000000 microorganisms.
The death rate is :
0.23 minutes for 1ml that is it takes 0.23 minutes to kill 30000 microorganisms.
The total time taken is thus :
3000000 / 30000 × 0.23 = 23 minute.
The time taken is thus :
23 minutes.
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