It's Ans is 10.8 V.Ans this with explanation please!!
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1
heya.......
---Answer:
so ur option answer is wrong dude...i hope it will help u..
tysm....@gozmit
---Answer:
The potential difference is =3.69V
We apply the equation
U=RI
E−U=rI
E=(R+r)I
The emf is E=2⋅1.9=3.8V
The cells are in series-parallel and the internal resistances as well.
The total resistance is
r+R=(12+12)+18=19Ω
The current is
I=3.919=0.21A
So, the potential difference is
=U=18⋅0.21=3.69V
so ur option answer is wrong dude...i hope it will help u..
tysm....@gozmit
Anonymous:
Nice answer :)
Answered by
0
Hey mate!
Here's your answer!!
The potential difference is = 3.69V
Explanation:
We apply the equation,
U = RI
E - U = rI
E = (R + r) I
The emf is E = 2• 1.9 = 3.8V
The cells are in series-parallel and the internal resistances as well.
The total resistance is,
The current is,
So, the potential difference is,
= U = 18• 0.21 = 3.69V.
✌ ✌
#BE BRAINLY
Here's your answer!!
The potential difference is = 3.69V
Explanation:
We apply the equation,
U = RI
E - U = rI
E = (R + r) I
The emf is E = 2• 1.9 = 3.8V
The cells are in series-parallel and the internal resistances as well.
The total resistance is,
The current is,
So, the potential difference is,
= U = 18• 0.21 = 3.69V.
✌ ✌
#BE BRAINLY
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