Question

it's for Ur practice
I have done it​

Answer 1

Hello mate,

Here is your answer,

Given:

• Two taps together can fill a tank in 15/8 hours

• The tap with longer diameter takes 2 hours less time to fill the tank

To Find:

• The time taken by each tap to fill the tank

Solution:

• Let time taken for the first tap to fill the tank = 'x' hours.

• So the time taken by the other tap to fill the tank = '(x - 2)' hours.

Total time taken by both taps to fill the tank = x + (x - 2) hours

=> 2(x - 2) hours

As given that the taps together fill the tank in 15/8 hours,

2(x - 2) = 15/8

x - 2 = 15/16

x = 47/16

x = 2.93 hours

= 3 hours (approximately)

Now substituting the value of 'x',

First tap => 'x' hours

= 3 hours

Second tap => (x - 2) hours

= 1 hour

Hope it helps:)

Answer 2

Both Tap can fill the tank in = 15/8 hours ..

since y > x (Assume y with larger diameter)

Either we can solve it by x .

$\frac{1}{x} + \frac{1}{x - 2} = \frac{8}{15}$

8(x²-2x) = 15(2x-2)

8x²-16x-30x+30 = 0

8x²-46x+30 = 0

4x²-23x+15 = 0

4x²-20x-3x+15 = 0

4x(x-5)-3(x-5) = 0

(4x-3)(x-5) = 0

x = 5 Hours (Ans)

y = 5-2 = 3 hours (Ans)

(Hope it Helps you)