Question

It's my homework...and the one who solves this correctly will be my brainliest man...or women...
Solve question no. 4 ,5, 6,7...plz need the solution right now tomorrow I gotta show it to my teacher.

Answer 1

Hello!

It's the time to unlock your question!

4)
$\alpha + \beta = \frac{ - 1}{2}$
$\alpha \beta = - 3$
Since α  and β are the zeroes of a quadratic polynomial , then the quadratic polynomial :-

x²- (sum of zeroes) x + product of zeroes

Required polynomial =>

x² - (-1/2)x + (-3)

x² + 1/2x - 3 ==> Answer.

6) Sum of zeros =

$\frac{3 + \sqrt{5} \: }{2} + \frac{3 - \sqrt{5} }{2}$
$= 3$
Product of zeros =

$( \frac{3 + \sqrt{5} }{2})( \frac{3 - \sqrt{5} }{2} )$
Use => (a+b)(a-b) = a²-b²

$= 2$
Put this in formula =>

x² - (sum of zero's)x + (product of zero's)

x² - 3x + 2

5) Sum of zero's = 5-3√2 + 5+3√2

= 10

Product of zero's = (5+3√2)(5-3√2)

= -8

Putting it in formula ---›

x² - 10x - 8

Thanks!