Question

it takes 382 kJ energy to remove one mole of electrons from gaseous cesium, what is the wavelength associated with this energy?

Answer 1

The wavelength associated with this energy is$3.134\times 10^{-7}m$

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

$E=\frac{Nhc}{\lambda}$

where,

E = energy of the light  = 382 kJ= 382000 J   (1kJ=1000J)

N= moles = 1 = $6.023\times 10^{23}$

h = Planck's constant  = $6.626\times 10^{-34}Js$

c = speed of light  =$3\times 10^8m/s$

$\lambda$ = wavelength of light  = ?

When $\lambda=600nm$, then the equation becomes:

$382000J=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}Js\times 3\times 10^8m/s}{\lambda}$    

${\lambda}=3.134\times 10^{-7}m$

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