Question

its questions for 10 th class

Answer 1

Heya!!

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Suppose we have to find eq resistance btw B nd C.

Since AB and AC are in series.

=) 8 ohm + 8 ohm = 16 ohms.

Then 16 ohm nd 8 ohms are in parallel.

=) 1/R = 1/16 + 1/8

=) 1/R = 3/16

=) R = 16/3 ohm

Hope it helps uh!!

Answer 2

Hey there !

Solution:

Refer to the attachment for the diagram !

According to the diagram, AB and AC are connected in a series connection.

=> Net Resistance = 8 + 8 = 16 Ω

Now BC and AB +AC are connected in Parallel connection.

Hence Net Resistance offered here is :

1 / R = 1 / 8 + 1 / 16

=> 1 / R = 2 / 16 + 1 / 16

=> 1 / R = 3 / 16

=> R = 16 / 3 Ω

Hence BC is the resistance between two terminals.

Hence we can say that the net resistance between two terminals is 16/3 Ω.

Hence Option ( d ) is correct.

Hope my answer helped !