Question

JEE ADVANCED CHEMISTRY QUESTION SEPTEMBER 2020

Answer 1

ANSWER.

The minimum temperature (k) at which the

reduction of cassiterite be Coke would take

place = 935k

EXPLANATION.

$\sf : \implies \: at \: 298k : \: \Delta_{f}H {}^{0} ( sno_{2}(s)) = - 581.0 \: kj \: mol {}^{ - 1} \\ \\ \sf : \implies \: \Delta_{f}H {}^{0}( co_{2}(g)) = - 394.0 \: kj \: mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0} ( sno_{2}(s)) = 56.0 \: jk {}^{ - 1} \: mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0} (sn(s)) = 52.0jk {}^{ - 1} mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0}( co_{2}(g)) = 210.0j {k}^{ - 1} mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0} (c(s)) = 6.0jk {}^{ - 1} mol {}^{ - 1}$

$\sf : \implies \: \Delta \: H {}^{0} = - 394 - ( - 581) \\ \\ \sf : \implies \: \Delta \: H {}^{0} \: = 187000 \: joule \\ \\ \sf : \implies \: \Delta \: {s}^{0} = {s}^{0} co_{2} + {s}^{0}sn - {s}^{0} sno_{2} - {s}^{0}c \\ \\ \sf : \implies \: \Delta \: {s}^{0} = 210 + 52 - 56 - 6 \\ \\ \sf : \implies \: \Delta \: {s}^{0} \: = 200 \: joule$

$\sf : \implies \: \: \Delta \: {G}^{} = \Delta \: H \: - T\Delta \: S \: \\ \\ \sf : \implies \: 0 = 18700 -T(200) \\ \\\sf : \implies \: T \: = \frac{187000}{200} = 935k$

Answer 2

ANSWER.

The minimum temperature (k) at which the

reduction of cassiterite be Coke would take

place = 935k

EXPLANATION.

$\sf : \implies \: at \: 298k : \: \Delta_{f}H {}^{0} ( sno_{2}(s)) = - 581.0 \: kj \: mol {}^{ - 1} \\ \\ \sf : \implies \: \Delta_{f}H {}^{0}( co_{2}(g)) = - 394.0 \: kj \: mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0} ( sno_{2}(s)) = 56.0 \: jk {}^{ - 1} \: mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0} (sn(s)) = 52.0jk {}^{ - 1} mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0}( co_{2}(g)) = 210.0j {k}^{ - 1} mol {}^{ - 1} \\ \\ \sf : \implies \: {s}^{0} (c(s)) = 6.0jk {}^{ - 1} mol {}^{ - 1}$

$\sf : \implies \: \Delta \: H {}^{0} = - 394 - ( - 581) \\ \\ \sf : \implies \: \Delta \: H {}^{0} \: = 187000 \: joule \\ \\ \sf : \implies \: \Delta \: {s}^{0} = {s}^{0} co_{2} + {s}^{0}sn - {s}^{0} sno_{2} - {s}^{0}c \\ \\ \sf : \implies \: \Delta \: {s}^{0} = 210 + 52 - 56 - 6 \\ \\ \sf : \implies \: \Delta \: {s}^{0} \: = 200 \: joule$

$\sf : \implies \: \: \Delta \: {G}^{} = \Delta \: H \: - T\Delta \: S \: \\ \\ \sf : \implies \: 0 = 18700 -T(200) \\ \\\sf : \implies \: T \: = \frac{187000}{200} = 935k$

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