Question

Jitendra's age is three times the sum of the ages of his two sons two years ago his age was six years less than four times the sum of the ages of his sons what is the present age of jitendra

Answer 1

Let the present ages of first son, second son and jitendra be a, b and 3 (a+ b)

According to question

3(a+b) - 2 + 6 = 4 (a - 2 + b-2)

=> 3a + 3b + 4 = 4a + 4b - 16

=> a + b = 20

Jitendra's present age = 3 (a+b)

= 3 (20)

= 60 years

Answer 2

Answer:

60 years

Step-by-step explanation:

Let the age of two sons be x and y

We are given that Jitendra's age is three times  the sum of the ages of his two sons

So, Father's present age = 3(x+y)

We are given that two years ago his age was six years less than four times the sum of the ages of his sons

Ages of son 2 years ago = x-2 and y-2

Father's age 2 years ago = 3(x+y)-2

So, ATQ

3(x+y)-2 = 4(x-2+y-2)-6

x+y=20

Father's present age = 3(x+y) =3(20)=60

Hence  Father's present age is 60 years