Math, asked by jitendra9951, 1 year ago

Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was ???​

Answers

Answered by poojachoudhary09
3

Answer:

your answer is here !

Step-by-step explanation:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: twice as much.

follow me !

Answered by tamal94
2

Step-by-step explanation:

Let speed of the 1st trip x miles/hr. and

speed of the 2nd trip 3x/hr.

You know speed formula..

Speed = Distance/Time.

Or Time = Distance/Speed.

times taken to covered

a distance of 50 miles on his first trip

50/x hr. Okey

Then.

And times taken to covered a distance of

300 miles on his later trip 300/3x hr.

= 100/x hr.

Similar questions